First a little physics is required

P = E/t
( P in watts, E in Joules, t in seconds )

Calculate the change in heat of the substance

delta h = C*m*delta T
( h in Joules, C specific heat capacity JK-1 g-1,
m mass in gms, T in degrees K
Cwater = 4.2 JK-1 g-1)

Assuming no energy losses by conductance from fluid to surroundings and using a 250 watt heater in a 200 litre reservoir with the water at 12 degrees Centigrade how long will the heater have to be on to raise the water to 22 degrees Centigrade ?

P*t = C*m*dT
t = (C*m*dT)/P


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Home arrow FAQ arrow Hydroponicsarrow How long will it take my heater to warm my nutrient ?
How long will it take my heater to warm my nutrient ?
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First a little physics is required

P = E/t
( P in watts, E in Joules, t in seconds )

Calculate the change in heat of the substance

delta h = C*m*delta T
( h in Joules, C specific heat capacity JK-1 g-1,
m mass in gms, T in degrees K
Cwater = 4.2 JK-1 g-1)

Assuming no energy losses by conductance from fluid to surroundings and using a 250 watt heater in a 200 litre reservoir with the water at 12 degrees Centigrade how long will the heater have to be on to raise the water to 22 degrees Centigrade ? ...

250*t

= E = 4.2*dT*m

 

= 4.2*10*200*1000

t

= (4.2*10*200)/250

 

= 33.6*10E3 sec

 

= 9.3 hours

At 12 cents per kilowatt hour this will cost

(( 250*9.3 )/1000)*12 cents = $ 0.28


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